leetcode-211 Add and Search Word - Data structure design

Design a data structure that supports the following two operations:

  • void addWord(word)
  • bool search(word)

search(word) can search a literal word or a regular expression string containing only letters a-z or .. A . means it can represent any one letter.

Example:

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addWord("bad")
addWord("dad")
addWord("mad")
search("pad") -> false
search("bad") -> true
search(".ad") -> true
search("b..") -> true

Note:

  • You may assume that all words are consist of lowercase letters a-z.

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class TrieNode{
public:
bool word;
TrieNode* children[26];
TrieNode(){
word = false;
memset(children, NULL, sizeof(children));
}
};



class WordDictionary {
public:
/** Initialize your data structure here. */
WordDictionary() {

}

/** Adds a word into the data structure. */
void addWord(string word) {
TrieNode* node = root;
for(char c: word)
{
if(!node->children[c-'a']){
node->children[c-'a'] = new TrieNode();
}
node = node->children[c-'a'];
}
node->word = true;
}

/** Returns if the word is in the data structure. A word could contain the dot character '.' to represent any one letter. */
bool search(string word) {
return search(word.c_str(), root);
}

private:
TrieNode* root = new TrieNode();

bool search(const char* word, TrieNode* node){
for(int i=0; word[i] && node; i++){
if(word[i] != '.'){
node = node->children[word[i]-'a'];
}
else{
TrieNode* tmp = node;
for(int j=0; j<26; j++){
node = tmp->children[j];
if(search(word+i+1, node)){
return true;
}
}
}
}
return node && node->word;
}
};

/**
* Your WordDictionary object will be instantiated and called as such:
* WordDictionary* obj = new WordDictionary();
* obj->addWord(word);
* bool param_2 = obj->search(word);
*/
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