leetcode-341 Flatten Nested List Iterator

Given a nested list of integers, implement an iterator to flatten it.

Each element is either an integer, or a list – whose elements may also be integers or other lists.

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Example 1:

Input: [[1,1],2,[1,1]]
Output: [1,1,2,1,1]
Explanation: By calling next repeatedly until hasNext returns false,
the order of elements returned by next should be: [1,1,2,1,1].
Example 2:

Input: [1,[4,[6]]]
Output: [1,4,6]
Explanation: By calling next repeatedly until hasNext returns false,
the order of elements returned by next should be: [1,4,6].
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/**
* // This is the interface that allows for creating nested lists.
* // You should not implement it, or speculate about its implementation
* class NestedInteger {
* public:
* // Return true if this NestedInteger holds a single integer, rather than a nested list.
* bool isInteger() const;
*
* // Return the single integer that this NestedInteger holds, if it holds a single integer
* // The result is undefined if this NestedInteger holds a nested list
* int getInteger() const;
*
* // Return the nested list that this NestedInteger holds, if it holds a nested list
* // The result is undefined if this NestedInteger holds a single integer
* const vector<NestedInteger> &getList() const;
* };
*/
class NestedIterator {
private:
stack<NestedInteger> s;
public:
NestedIterator(vector<NestedInteger> &nestedList) {
int len = nestedList.size();
int i = 0;

for(i = len-1; i>=0; i--){
s.push(nestedList[i]);
}
}

int next() {
NestedInteger temp = s.top();
s.pop();
return temp.getInteger();
}

bool hasNext() {
while(!s.empty()){
NestedInteger temp = s.top();
if(temp.isInteger())
return true;
else{
s.pop();
vector<NestedInteger> List = temp.getList();
int len = List.size();
int i = 0;

for(i = len-1; i>=0; i--){
s.push(List[i]);
}
}
}
return false;
}
};

/**
* Your NestedIterator object will be instantiated and called as such:
* NestedIterator i(nestedList);
* while (i.hasNext()) cout << i.next();
*/
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